C -----------------------------------------------------------
      subroutine blet1(ilet,alet1)
c

	CHARACTER*1 IN(0:9)
	integer*1 ilet
	DATA IN/'0','1','2','3','4','5','6','7','8','9'/
	CHARACTER*1 alet1
	a1='0'
	j1=ilet
    5	do i=0,9
     	if (j1.eq.i) then
 	alet1=IN(i)
	endif
	enddo 
	return
	end
C
      subroutine blet2(ilet,alet2)
c

	CHARACTER*1 IN(0:9)
C-	integer*2 ilet
	DATA IN/'0','1','2','3','4','5','6','7','8','9'/
	CHARACTER*2 alet2
	a2='00'
	j10=ilet/10
	j1=ilet-j10*10
    5	do i=0,9
	if (j10.eq.i) then
	alet2(1:1)=IN(i)
	endif
	enddo
   7	do i=0,9 
     	if (j1.eq.i) then
 	alet2(2:2)=IN(i)
	endif
	enddo 
	return
	end
C
      subroutine blet3(ilet,alet3)
c     nn=1,2,3,4 

	CHARACTER*1 IN(0:9)
	DATA IN/'0','1','2','3','4','5','6','7','8','9'/
	CHARACTER*3 alet3
	a3='000'
C
	j100=ilet/100
	      j10=(ilet-j100*100)/10
	j1=ilet-j100*100-j10*10
    3	do i=0,9
		if (j100.eq.i) then
	alet3(1:1)=IN(i)
	endif
	enddo
    5	do i=0,9
	if (j10.eq.i) then
	alet3(2:2)=IN(i)
	endif
	enddo
   7	do i=0,9 
     	if (j1.eq.i) then
 	alet3(3:3)=IN(i)
	endif
	enddo 
	return
	end
C
C Convert numeric parameter ilet to character alet
      subroutine blet4(ilet,alet4)
c     nn=1,2,3,4 

	CHARACTER*1 IN(0:9)
		DATA IN/'0','1','2','3','4','5','6','7','8','9'/
      CHARACTER*4 alet4
	alet4=' 000'
C
   1		j1000=ilet/1000
	      j100=(ilet-j1000*1000)/100
	j10=(ilet-j1000*1000-j100*100)/10
	j1=ilet-j1000*1000-j100*100-j10*10
	do i=0,9
		if (j1000.eq.i) then
	 alet4(1:1)=IN(i)
	endif
	enddo
	if(alet4(1:1).eq.'0') alet4(1:1)=' '
    3	do i=0,9
		if (j100.eq.i) then
	 alet4(2:2)=IN(i)
	endif
	enddo
c	if((alet4(1:1).eq.' ').and.(alet4(2:2).eq.'0')) alet4(2:2)=' '
    5	do i=0,9
	if (j10.eq.i) then
	alet4(3:3)=IN(i)
	endif
	enddo
   7	do i=0,9 
     	if (j1.eq.i) then
 	alet4(4:4)=IN(i)
	endif
	enddo 
	return
	end
C
      integer function ndoy(iyr,imn,idy)
C To define day-of-year
C
	       DIMENSION IM(12)
	integer*2 iyr,imn,idy
	DATA IM/31,28,31,30,31,30,31,31,30,31,30,31/
	z1=iyr/4.0
      jz1=int(z1)*4
      IF(jz1.EQ.iyr) THEN
               IM(2)=29
        ELSE
                IM(2)=28
	       ENDIF
C Day-of-year LDA1
		mosum=0
      if(imn.gt.1) then
         do 1234 i=1,imn-1
1234    mosum=mosum+im(i)
         endif
      ndoy=mosum+idy	
	END FUNCTION
C ===============================================================